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I have the following requirement for hashing using MD5.

H(A,B,C,X);

Where values A,B & C are given. However X is not given.

I would like to find out what value of X would give a hash beginning with 32 1's bits

meaning H(A,B,C,X) = Begin with 32 '1' bits

I can brute force by testing all kinds of characters of X till i get 32 '1' bits.

however is there a faster way rather than doing this?

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Don't cross-post on different SE sites please. – CodesInChaos Nov 4 '12 at 17:11
Closed as off topic - your cross-post on Crypto is more appropriate there. – Rory Alsop♦ Nov 4 '12 at 17:22

closed as off topic by Rory Alsop♦ Nov 4 '12 at 17:21

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