Take the 2-minute tour ×
Information Security Stack Exchange is a question and answer site for Information security professionals. It's 100% free, no registration required.

Language safety is not clearly defined while there're warnings about for instance Java. So how can you say that language is not safe while language safety is not clearly defined? If Java is unsafe now, is Java version 7 "safer" than Java version 2?

share|improve this question
5  
I don't know that what you're referencing is actually language safety. In the Java example, the rash of recent vulnerabilities are not intrinsic to, or an indictment of the Java language, but flaws in the Java Runtime Environment. –  Xander Mar 6 '13 at 16:17
    
Ok so what we mean is Java as an environment rather than a language. I can accept and understand that. –  Niklas rtz Mar 6 '13 at 16:38
1  
This question is a bit of a rant, and seems to treat "safe" as if it were a binary (it's either safe or unsafe). In practice, safety is a matter of shades of grey: some systems may be riskier than others, and no computer system is ever completely safe. –  D.W. Mar 6 '13 at 19:04
    
@D.W. Yes, I expect to be asked the binary black and white yes-or-no question Is it safe? Answer only yes or only no. I've added what are the "shades" of safety between version 2 and version 7. –  Niklas rtz Mar 6 '13 at 22:30

4 Answers 4

up vote 5 down vote accepted

A language can be said to be "safe" if it is possible to implement its interpreter/compiler/runtime environment efficiently, in full respect of the language specification, and still forcibly preventing "bad things" to happen. Then it depends on what "bad things" you are talking about.

Java is "safe" if you want to protect the machine from the code written by the developer. Array bounds are checked, types are unescapable, and memory deallocation is handled by a garbage collector, which means that it is not theoretically feasible to make a Java applet, however poorly written, execute attacker-chosen native code. In the same conditions, C is "unsafe" because it cannot be fully implemented with checks which prevent arbitrary code execution.

Of course, in practice, things change a bit: C code can be made "safer" with various techniques (like DEP and ASLR) and the OS can "contain" native code under some specific access rights (a "normal user" process is not root). And Java actuality shows us that while Java is theoretically safe, the implementation of the Java Virtual Machine and its runtime environment can have holes. To some extent, the exact JVM specification ensures that implementing Java safely is hard (that's a misfeature of the Applet model: it forces per-method control throughout the whole standard library).

You cannot have a one-size-fits-all definition of language safety, unless you are content with a subjective slogan (COBOL sucks ! F# rules ! Prolog forever !). It all depends on the context.

share|improve this answer

There may be some confusion here. A programming language does not inherently include vulnerabilities. It is the programs written in those languages that do.

Higher level languages (like Perl, Java, JavaScript, C#, but not C or C++) help simplify your programming code, and will allow you to write your code such that a buffer overflow is not possible which is better for security, but the security difference between high level languages is very small.

In the case of Java, there is a sandbox which has not proven to be entirely effective. This sandbox was intended to allow a program to be written in Java, and then to run in the browser, without having access to the computer it was running on. It is the Java sandbox that has had security problems, not Java itself. I cannot speak to the comparison between Java 7 and Java 2.

share|improve this answer
1  
The java sandbox is a construct of the jvm and has nothing to do with a browser other than that browser utilizing a jvm. Also, the majority of the problems that have been uncovered with java have very little to the with the 'sandboxing mechinism' but have exposed inconsistent and/incompatible implementations of the security manager. –  grauwulf Mar 6 '13 at 16:22
1  
@grauwulf: Isn't the security manager supposed to control what the sandboxed software is allowed to do? If the security manager is broken, the sandbox won't work as expected either. –  jarnbjo Mar 6 '13 at 16:37
1  
Fair enough @jarnbjo but they are two distinct aspects of the VM and each has a discrete utility. Hence; comment and not dv :-P –  grauwulf Mar 6 '13 at 18:05

Languages are classified as safe and unsafe based upon a few properties. A safe language as you say include at least the following properties:

  1. Type safety: All the variables are of a particular type (int, float, string etc) and have clearly defined minimum and maximum length values.
  2. Bound Checking: Array bounds are checked before performing array operations. This means no operation is allowed to access an array object beyond the minimum array location (which is zero) and maximum array location
  3. Automatic Memory Management: Memory management such as allocation/deallowcation is performed automatically by the runtime. This is also called garbage collection. When a block of code is out of scope, all the variables are automatically freed.
  4. Sandbox Environment: The programs are run in a restricted environment and can't interact with the OS and/or file system directly.

Java language has all these properties and hence can be easily classified as a "safe" language. The insecurity you mentioned is not because of the language itself but due to insecure sandbox environment and insecure library calls. Take apart any recent Java exploit code and all it does is bypassing security restrictions to call privileged class code. It has nothing to do with the insecurity of the language itself but with the complex and insecure design of the java libraries.

share|improve this answer

Language safety can be interpreted more broadly than affecting merely security. But as this is a security site, let's just restrictive ourselves to security.

Clearly language selection has a significant on whether you will get certain types of vulnerability. Write a non-trivial program in C and it will be full of memory corruption errors (buffer overflow, use-after-free, etc).

There a couple of useful definitions:

Memory-safe - This means a program within the language cannot access memory outside of allocations. No running beyond a buffer or using a allocation after it has been freed. That's tricky to automatically prove for a language like C. Memory-safety is typically achieved through garbage collection and using the more restrictive type-safety.

Type-safe - Don't confuse this with just not messing up your types in unsafe languages. This is a guarantee which goes beyond memory-safety in that you cannot use a type in a way inappropriate to the actual type of the object. You can't treat a pointer as an integer, for example.

Interestingly, from 1.5 Java is not vanilla type-safe. It is type-safe with respect to raw types, as used by the JVM and Java language 1.4 and earlier. It is unsafe with respect the full language type system including generics. This doesn't seem to matter at all, largely because in order to access an object the bytecode must perform a raw type check.

For non-memory corruption vulnerabilities libraries become more important. For instance, injection is an incredibly popular class of vulnerability, but there's not really any excuse in having any at all.

Mobile code (that is code that is mobile and untrusted) is an altogether different thing. Safety can be achieved via a sandbox (as Google's NaCl), an Object-Capability Model (jargon essentially meaning OOP in a type-safe environment) or some combination of the other two.

As for Java SE 1.7 vs 1.2. There hasn't been much change. 1.2 is very different to 1.1, and 1.0 was a bit different again (although really before I was paying attention to these sorts of things).

Specific issues in the Java language which do cause vulnerabilities:

  • static (for fields, when not immutable) is a one keyword way of introducing vulnerabilities and wrecking code quality.
  • Incredibly poor support for (immutable) value types.
  • Methods in Object and Java Serialisation (I'm including as part of the language due to transient keyword and an implementation that isn't even possible in bytecode) are dodgy.
  • Allowing fields to be seen uninitialised (though zerod) which may be given an unsafe interpretation.
  • All integer types overflow. Although as Java is memory safe this rarely matters. It does matter for validating arguments to native/intrinsic code or resource management.
share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.