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Aug 6, 2020 at 14:12 comment added Phil @schroeder even without a 1:1 ratio of balls, if I put x black balls in, I can deduce if anyone else voted with me if there are >x black balls. Potentially if a voter in my scheme accurately weighed the salt beforehand and accurately weigh the residue after, they could make a similar deduction, but this could be trivially prevented by a washing the pan before anyone has a chance to weigh it.
Aug 6, 2020 at 11:39 comment added schroeder You assume a 1:1 ratio of balls to voters.
Aug 6, 2020 at 11:37 comment added rumtscho @schroeder with blackball, you can afterwards count how many black balls were cast, which violates the requirements. With this scheme, you can never say how many people put salt in.
Aug 6, 2020 at 11:00 comment added schroeder This is simply a salt-based version of the "blackball" scheme.
Aug 5, 2020 at 7:13 comment added Phil @Woj I had intended that the glasses be poured into the pan at the same time. Updated to clarify.
Aug 5, 2020 at 7:12 history edited Phil CC BY-SA 4.0
added 15 characters in body
Aug 4, 2020 at 18:43 comment added Brian After being filled with water but before salt is added, the pan is in public view. All participants can watch the pan and can attack anyone who attempts to perform unauthorized sampling.
Aug 4, 2020 at 15:56 comment added WoJ The problem is that the current voter (the further they are in the voting line, the better) can check (by sampling the water) if someone has already voted "salt" or not.
Aug 4, 2020 at 12:47 review First posts
Aug 4, 2020 at 13:53
Aug 4, 2020 at 12:45 history answered Phil CC BY-SA 4.0