0

I am giving the following (masked) BTC Private Key:

L2nBmWGfAH5Vf9re41VhG6BgPx25rxqGmkbaPtG14jAPtBUzhQab

What I can tell you is that the key above has 3 incorrect characters in it at different random spots. The incorrect 3 characters can be either the same letter or different, in both UPPER or lowercase.

But let's assume all 3 chars are the same letter in the same case (eg. A A A)

The alphabet has 26 letters with each having both uppercase and lowercase forms.

Considering that, we also know that the key is 52-char long.

What are the chances of someone cracking the key and successfully find the correct letters missing in it?

What calculations and permutations do we have to do ?

26x26x26...x26 , 52 times ?

If the exact location of the incorrect letters was known, I guess the calculations were much easier.

But in this case, the exact locations are secret because I try to understand how many permutations/chances are required to do, to find them.

How is it done? Is it even possible to crack the incorrect 3 missing letters or not?

Thanks

New contributor
R R is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct.
2

0

Browse other questions tagged .