can't we just go through the compiler's source code and check for any backdoor, what was the article's point?
The whole point of the article is that can't do that because the backdoor is not in the compiler's source code.
Thompson explains this in various steps:
You put a backdoor in the source code of the login program. Obviously, when you examine the ...
Is it possible to exploit this code?
How can an attacker exploit this?
Path Traversal Vulnerabilities allow an attacker to choose a file that is not intended by the developer.
For example, your program has the path "C:\\Users\\kutrivedi\\Desktop\\Ref\\" + input + ".txt" hardcoded. If I entered foo as input, then the resulting file would be C:\\...
No, because the source you can see doesn't necessarily match up with the binary you're using. The specific attack described in that paper involves multiple compiler source versions: there is a malicious one, which contains the code to inject backdoors into anything compiled using this compiler, and a clean one, which doesn't contain this code.
The attacker ...
The assert function will be called with one static parameter, the string is_string($entityId).
Thanks to the usage of single quotes, $entityId won't be interpolated, so an attacker won't be able to execute any PHP code.
A compiler creates a binary from source code. For a normal compiler, the binary is just another representation of the source code, and the behavior of the program is fully specified in the source. However, a malicious compiler can add extra functionality in the binary, functionality that is not present in the source and thus can not be detected by reading ...
All my github repos have requirements.txt files in them, and GitHub will email you a warning if there are security issues. (it appears that GitHub will scan any file named requirements.txt anywhere in your repo)
The dependency graph will also display some information.
As a previous commenter mentioned synk which is a nice tool, I found that for python, ...
Why are you using %00 at the end of your input? You're getting it "free" :) from the code itself in the . ".php" part
I'm guessing that the challenge is not in PHP7, since you can't terminate strings like that any more.
Anyway, using the payload ../etc/config (without null - %00) works for me:
However, maybe my setup is wrong: